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  • Orélie
  • Orélie's Avatar
23 Apr 2024 11:03 - 23 Apr 2024 11:05
 

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Your LimeSurvey version: LimeSurvey Cloud   Version 6.5.4
Own server or LimeSurvey hosting: Limesurvey hosting
Survey theme/template: Fruity 23
==================

Hello,

I made a survey with 3 randomly displayed groups (see attached lss file).

I'd like to display the 1st group to 10% of the participants, the 2nd group and the 3rd groups to 45% of the participants.

Does anyone have the correct syntax?

Thanks a lot!
  • rajkumar_dms
  • rajkumar_dms's Avatar
23 Apr 2024 10:44 - 23 Apr 2024 14:21
Please help us help you and fill where relevant:
Your LimeSurvey version: [6.5]
Own server or LimeSurvey hosting:Clould
Survey theme/template:
==================
I would like the below compile the below syntax in lime survey, can i compile it 
<script type="text/javascript">
  $(document).on('ready pjax:scriptcomplete',function(){
function shuffleArray(array) {
    for (let i = array.length - 1; i > 0; i--) {
        const j = Math.floor(Math.random() * (i + 1));
        [array, array[j]] = [array[j], array];
    }
    return array;
}

// Example: Customizing rotation for a multiple choice question
$(document).ready(function() {
    // Identify the question by its ID or class
    var questionId = $('#question{QID}'); // Change to the appropriate ID or class

    // Get the answer choices container
    var answerChoicesContainer = $(questionId).find('.answer-choices');

    // Get the answer choices
    var answerChoices = answerChoicesContainer.children('.answer-item');

    // Array to store fixed elements
    var fixedElements = [2,4,6];

    // Loop through answer choices to find fixed elements
    answerChoices.each(function() {
        if ($(this).hasClass('fixed')) { // Assuming 'fixed' is a class added to fixed elements
            fixedElements.push($(this));
        }
    });

    // Remove fixed elements from the answer choices array
    fixedElements.forEach(function(element) {
        answerChoices = answerChoices.not(element);
    });

    // Shuffle the remaining answer choices
    var shuffledChoices = shuffleArray(answerChoices);

    // Insert fixed elements back into the shuffled choices array
    fixedElements.forEach(function(element) {
        shuffledChoices.splice(element.data('position'), 0, element); // Assuming 'position' is a data attribute indicating the fixed position
    });

    // Append the shuffled choices back to the container
    answerChoicesContainer.empty().append(shuffledChoices);
});
</script>
  • rajkumar_dms
  • rajkumar_dms's Avatar
22 Apr 2024 19:54
Thanks joffm

You are the genius joffm

Thank you
  • DenisChenu
  • DenisChenu's Avatar
22 Apr 2024 10:52
Le plus simple selon ce que tu expliques me semble d'utiliser plutôt la rotation des groupes, à tester
  1. Tu places les groupes dans le même « Nom de groupe aléatoire »
  2. Tu ajoutes dans chaque groupe une question de type équation avec 1 comme formule. EQG1, EQG2,EQG3 etc …
  3. Tu ajoutes la condition : sum(EQG1.NAOK, EQG2.NAOK,EQG3.NAOK…) < 3 OR EQG1.NAOK sur chaque groupe (le dezrnier EQG1 est à modifier pour chaque groupe)
  4. Tu test

> Cependant, je ne parviens pas à appliquer l'équation conditionnelle "random == 1 AND random2 == 1" aux groupes de métiers, car cela entraîne un dysfonctionnement complet du questionnaire.

Qu'est ce qui ne fonctionne pas ? C'ets pas clair du tout.
 
  • Joffm
  • Joffm's Avatar
21 Apr 2024 14:00
Exact.
N x 3 + 1 (for final)

Joffm 
  • Mazi
  • Mazi's Avatar
21 Apr 2024 13:06
Thanks a lot for this detailed explanation, joffm!

So If I get this right, when extending this from top3 to top5 we will end up with 16 RC sub-questions?!
  • Joffm
  • Joffm's Avatar
19 Apr 2024 18:30 - 19 Apr 2024 18:32
Hi,
Let's say the first multiple question is Q1 with subquestion codes 1, 2, 3, ...
To do this I prefer to create a "container" to store interim results
1. Create a question of type "multiple short text" (I called it "RC" like "Result Container") with subquestions
RC_11
RC_12
RC_13
RC_21
RC_22
RC_23
RC_31
RC_32
RC_33
RC_99 (for the final result)
Three subquestions are needed for each element

2. Create a question of type "equation" and enter (only) the equations
First create the base:
{RC_11=join(if(Q1_1=="Y","A",""),if(Q1_2=="Y","B",""),if(Q1_3=="Y","C",""),if(Q1_4=="Y","D",""),if(Q1_5=="Y","E",""),if(Q1_6=="Y","F",""),if(Q1_7=="Y","G",""),if(Q1_8=="Y","H",""),if(Q1_9=="Y","I",""),if(Q1_10=="Y","J",""))}
We get something like "ADEGIJ"
Now the procedure I explained before
Random number from 1 to the length of this string
{RC_12=if(is_empty(RC_12),rand(1,strlen(RC_11)),RC_12)}

Capture the letter at this position
{RC_13=substr(RC_11,RC_12-1,1)}

Remove the letter at this position; this is the base for the next round
{RC_21=str_replace(RC_13,'',RC_11)}
{RC_22=if(is_empty(RC_22),rand(1,strlen(RC_21)),RC_22)}
{RC_23=substr(RC_21,RC_22-1,1)}


{RC_31=str_replace(RC_23,'',RC_21)}
{RC_32=if(is_empty(RC_32),rand(1,strlen(RC_31)),RC_32)}
{RC_33=substr(RC_31,RC_32-1,1)}


Now there are three letters (in RC_13, RC_23 and RC_33)

Joined with a  '#' (important for the function "strpos(x,y)")
{RC_99=join('#',RC_13,RC_23,RC_33)}

Now the conditions of the subquestions in Q2 are (just ask: Does the final strinf contain the letter)
strpos(RC_99,"A")>0
strpos(RC_99,"B")>0
strpos(RC_99,"C")>0

...


And there is this javascript solution.
Create a question of type "short text"
in the default answer enter
{list(if(Q1_1=="Y","A",""),if(Q1_2=="Y","B",""),if(Q1_3=="Y","C",""),if(Q1_4=="Y","D",""),if(Q1_5=="Y","E",""),if(Q1_6=="Y","F",""),if(Q1_7=="Y","G",""),if(Q1_8=="Y","H",""),if(Q1_9=="Y","I",""),if(Q1_10=="Y","J",""))}

and this script
Code:
<script type="text/javascript" charset="utf-8">
 
  function shuffle(array) {
    var currentIndex = array.length, temporaryValue, randomIndex;
    // While there remain elements to shuffle...
    while (0 !== currentIndex) {
      // Pick a remaining element...
      randomIndex = Math.floor(Math.random() * currentIndex);
      currentIndex -= 1;
      // And swap it with the current element.
      temporaryValue = array[currentIndex];
      array[currentIndex] = array[randomIndex];
      array[randomIndex] = temporaryValue;
    }
    return array;
  }
 
$(document).on('ready pjax:scriptcomplete',function(){
  // Fill the array
  var str = $('#question{QID} input[type="text"]').val();
  var arr=str.split(", ");
  arr = shuffle(arr).slice(0,3).join('');
  $('#question{QID} input[type="text"]').val('#' + arr);
});
</script>


Hide the question with css class "d-none"
and use the same subquestion conditions.

Joffm
  • rajkumar_dms
  • rajkumar_dms's Avatar
18 Apr 2024 20:14
Hi Holch,
Thanks for reply
Sorry for inconvenience
I doesn't mean for quick response,i just follow up the same
I thought he came back from vacation
  • holch
  • holch's Avatar
18 Apr 2024 20:01
What part of "He is on vacation and he will share it when he is back in Germany" did you not understand?

This is a forum where users help users. There is no right for a (quick) answer. Please be patient.
  • rajkumar_dms
  • rajkumar_dms's Avatar
18 Apr 2024 07:25
Hi,

Can you share the example for the same as per my wish
  • tpartner
  • tpartner's Avatar
17 Apr 2024 18:49
My solution would be to do as Joffm suggests - load the sub-question order in a hidden (via CSS class) short-text question. On page load, if that question is found to be populated, that order is used, otherwise your randomization alogorithm kick in.

Code:
<script type="text/javascript">
    $(document).on('ready pjax:scriptcomplete',function(){
 
        function shuffleArray(array) {
            for (var i = array.length - 1; i > 0; i--) {
                var j = Math.floor(Math.random() * (i + 1));
                var temp = array[i];
                array[i] = array[j];
                array[j] = temp;
            }
            return array;
        }
 
        // Merge function
        function mergeArrays(array1, array2) {
            var mergedArray = [];
            var maxLength = Math.max(array1.length, array2.length);
 
            for (var i = 0; i < maxLength; i++) {
                if (i < array2.length) {
                    mergedArray.push(array2[i]);
                }
                if (i < array1.length) {
                    mergedArray.push(array1[i]);
                }
            }
 
            return mergedArray;
        }
 
        // Identify some elements and define variables
        var thisQuestion = $('#question{QID}');
        var thisAnswerList = $('tr.answers-list:eq(0)', thisQuestion).parent();
        var thisTable = $('table.subquestion-list:eq(0)', thisQuestion);
        var orderQuestion = $(thisQuestion).nextAll('.text-short:eq(0)');
        var orderInput = $(':text.form-control:eq(0)', orderQuestion);
        var array_res;
        var aOrder = [];
 
        // Previously set order
        if($.trim($(orderInput).val()) != '') {
            array_res = $.trim($(orderInput).val()).split(',');
        }
        // No previous order set
        else {    
            // Special codes appear after
            var afterCode = 4;
 
            //Array for K Codes
            var array_k = ["b","d","g","h","i","j","l"];
 
            //Array for N Codes
            var array_n = ["c","e","f","k","m","n"];
 
            //Array for Special K Codes
            var array_sk = [];
 
            //Array for Special N codes
            var array_sn = ["a"];
 
            //Array for super special codes
            var array_ss = ["p"];
 
            // Shuffle order of "normal" arrays
            shuffleArray(array_k);
            shuffleArray(array_n);
 
            // Slice "normal" arrays and merge second part to special codes
            array_sk = array_sk.concat(array_k.slice(afterCode));
            array_sn = array_sn.concat(array_n.slice(afterCode));
 
            // Save only first part of "normal" arrays
            array_k = array_k.slice(0, afterCode);
            array_n = array_n.slice(0, afterCode);
 
            // Shuffle special arrays
            shuffleArray(array_sk);
            shuffleArray(array_sn);
            shuffleArray(array_ss);
 
            // Combine normal and special arrays
            array_k = array_k.concat(array_sk);
            array_n = array_n.concat(array_sn);
 
            // Merge arrays in order n,k,n,k...
            array_res = mergeArrays(array_k, array_n);
 
            //Add super special array to end of result array
            array_res = array_res.concat(array_ss);
 
            // Load the hidden order input
            $(orderInput).val(array_res);
        }
 
        // Loop through the answer codes
        $.each(array_res, function(i, val) {
            // Move the answer item
            $(thisAnswerList).append($('tr.answers-list[id$="X{QID}'+val+'"]', thisQuestion));
        });
 
        // Fix up the row background colours
        $('tr.answers-list', thisQuestion). each (function(i){
            $(this).removeClass('ls-even ls-odd');
            if(i % 2 == 0) {
                $(this).addClass('ls-even');
            }
            else {
                $(this).addClass('ls-odd');
            }
        });
    });   
 
</script>

Sample survey:  

File Attachment:

File Name: limesurvey...3182.lss
File Size:56 KB
  • BBSR-SR5
  • BBSR-SR5's Avatar
17 Apr 2024 18:22
Hm actually, I figured it might be easier to replace the Math.random() function with a seeded random function and then use the survey number as a seed. That way it should stay constant for a user.

Though how would I access that? Right now I've plugged in Date.now()
Code:
<script type="text/javascript" data-author="BBSR-SR5 &amp; Tony Partner">
  $(document).on('ready pjax:scriptcomplete',function(){
 
 
//Define Seeded Random function
   function splitmix32(a) {
  return function() {
    a |= 0;
    a = a + 0x9e3779b9 | 0;
    let t = a ^ a >>> 16;
    t = Math.imul(t, 0x21f0aaad);
    t = t ^ t >>> 15;
    t = Math.imul(t, 0x735a2d97);
    return ((t = t ^ t >>> 15) >>> 0) / 4294967296;
  };
}
 
function shuffleArray(array) {
  const seed = Date.now();
  const random = splitmix32(seed);
  for (let i = array.length - 1; i > 0; i--) {
    const j = Math.floor(random() * (i + 1));
    [array[i], array[j]] = [array[j], array[i]];
  }
  return array;
}
 
    // Merge function
        function mergeArrays(array1, array2) {
            var mergedArray = [];
            var maxLength = Math.max(array1.length, array2.length);
 
            for (var i = 0; i < maxLength; i++) {
                if (i < array2.length) {
                    mergedArray.push(array2[i]);
                }
                if (i < array1.length) {
                    mergedArray.push(array1[i]);
                }
            }
 
            return mergedArray;
        }
 
    //Identify this question
    var thisQuestion = $('#question{QID}');
    var thisAnswerList = $('tr.answers-list:eq(0)', thisQuestion).parent();
    var thisTable = $('table.subquestion-list:eq(0)', thisQuestion);
 
    // Special codes appear after
        var afterCode = 4;
 
        //Array for K Codes
        var array_k = ["b","d","g","h","i","j","l"];
 
        //Array for N Codes
        var array_n = ["c","e","f","k","m","n"];
 
        //Array for Special K Codes
        var array_sk = [];
 
        //Array for Special N codes
        var array_sn = ["a"];
 
        //Array for super special codes
        var array_ss = ["o"];
 
    // Shuffle order of "normal" arrays
        shuffleArray(array_k);
        shuffleArray(array_n);
 
 
        // Slice "normal" arrays and merge second part to special codes
        array_sk = array_sk.concat(array_k.slice(afterCode));
        array_sn = array_sn.concat(array_n.slice(afterCode));
 
        // Save only first part of "normal" arrays
        array_k = array_k.slice(0, afterCode);
        array_n = array_n.slice(0, afterCode);
 
        // Shuffle special arrays
        shuffleArray(array_sk);
        shuffleArray(array_sn);
        shuffleArray(array_ss);
 
        // Combine normal and special arrays
        array_k = array_k.concat(array_sk);
        array_n = array_n.concat(array_sn);
 
        // Merge arrays in order n,k,n,k...
        var array_res = mergeArrays(array_k, array_n);
 
        //Add super special array to end of result array
        array_res = array_res.concat(array_ss);
 
 
 
 
    // Loop through the answer codes
    $.each(array_res, function(i, val) {
      // Move the answer item
      $(thisAnswerList).append($('tr.answers-list[id$="X{QID}'+val+'"]', thisQuestion));
    });
 
 
 
 
    // Fix up the row background colours
        $('tr.answers-list', thisQuestion). each (function(i){
            $(this).removeClass('ls-even ls-odd');
            if(i % 2 == 0) {
                $(this).addClass('ls-even');
            }
            else {
                $(this).addClass('ls-odd');
            }
        });
 
      //alert(array_res);
    //console.log(array_res);
    });
 
 
 
</script>

How would I access the participant number from the code?
  • BBSR-SR5
  • BBSR-SR5's Avatar
17 Apr 2024 14:58 - 17 Apr 2024 15:10
Ich habe die Lösung selber gefunden. In dem fall aktiviert man einfach die Zufällig Antwortrotation und ergänzt folgenden Code im Fragefenster:
Code:
<script type="text/javascript" charset="utf-8">
 
$(document).on('ready pjax:scriptcomplete',function(){
 
// The number of answers to be fixed at the end of the list
var fixedAnswers = 1;
 
// Set this to "true" if you want "Other" to be fixed in the last position
var otherFixed = false;
 
// Identify this question
var qID = {QID};
 
// Find the number of answers
var ansCount = $('#question'+qID+' .answer-item').length;
if($('#question'+qID+' input[type="text"]').length > 0) {
ansCount = ansCount -1
}
console.log(ansCount);
 
// Place the last n answers created at the end of the list
var fixedIndex = fixedAnswers - 1;
for (var i=0; i<fixedAnswers; i++) {
var answer = $('input[id^="answer"][id$="X'+qID+(ansCount-fixedIndex)+'"]');
var answerItem = $(answer).closest('.answer-item');
var answersList = $(answer).closest('ul');
$(answersList).append(answerItem);
fixedIndex--;
}
 
// Handle "Other"
if(otherFixed == true &amp;&amp; $('#question'+qID+' input[type="text"]').length > 0) {
var otherAnswer = $('#question'+qID+' input[type="text"]');
var otherAnswerItem = $(otherAnswer ).closest('.answer-item');
var otherAnswersList = $(otherAnswer ).closest('ul');
$(otherAnswersList).append(otherAnswerItem);
}
});
</script>


Den Code habe ich aus dem manual hier btw: manual.limesurvey.org/Workarounds:_Manip...28radio.29_questions

Edit: Wichtiger Hinweis, der Code funktioniert nur wenn die Antwortoptionen mit Zahlen nummeriert sind.
1,2,3,4,5,6 geht
a,b,c,d,e,f geht nicht!
  • BBSR-SR5
  • BBSR-SR5's Avatar
17 Apr 2024 11:38
Danke für den Hinweis,

das habe ich jetzt so umgesetzt. Ich habe jetzt nur das Problem, dass ich gerne die Items rotieren möchte und das sonstige Item an seinem (letzten) Platz lassen möchte. Ich hatte gehofft, dass ich dafür einfach den Code aus den Matrix rotationen verwenden könnte:
Code:
<script type="text/javascript" data-author="Tony Partner">
  $(document).on('ready pjax:scriptcomplete',function(){
 
function shuffleArray(array) {
    for (var i = array.length - 1; i > 0; i--) {
        var j = Math.floor(Math.random() * (i + 1));
        var temp = array[i];
        array[i] = array[j];
        array[j] = temp;
    }
    return array;
}
    
    
    //Identify this question
    var thisQuestion = $('#question{QID}');
    var thisAnswerList = $('tr.answers-list:eq(0)', thisQuestion).parent();
 
    // Special codes appear after
    var afterCode=11;
    
    // Fill the array with "normal" codes
    var array1=[1,2,3,4,5,6,7,8,9,10,11];
    
    // Fill the array with "special" codes
    var array2=[12];
    shuffleArray(array1);
    array2=array2.concat(array1.slice(afterCode));
    array1=array1.slice(0,afterCode);
    shuffleArray(array2);
    array1=array1.concat(array2);
    
    alert(array1)
 
    // Loop through the answer codes
    $.each(array1, function(i, val) {
      // Move the answer item
      $(thisAnswerList).append($('tr.answers-list[id$="X{QID}'+val+'"]', thisQuestion));
    });
  });
</script>
Aber das funktioniert nicht. Während der array1 korrekt erzeugt wird, wird die Anordnung der Items nicht verändert. Ich nehme an, der Loop am Schluss muss dafür verändert werden, aber ich weiß nicht wie :)
  • rajkumar_dms
  • rajkumar_dms's Avatar
16 Apr 2024 20:11 - 17 Apr 2024 09:01
 
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