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Conjoint Analysis with some conditions
- RitaShen
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- Joffm
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11 months 3 weeks ago #243128
by Joffm
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Replied by Joffm on topic Conjoint Analysis with some conditions
Hi, Rita,
sorry, I do not understand why you suddenly wish a dependency between random5 and random6
this was your original code
And this was your requirement
condition1: KMT/DPP/NPP/TPP/NP (this is random5 - in the first column, resp. random6 in the second column)
condition2: lower high school/high school/Undergraduate/Graduate (this is random7 - in the first column, resp. random8 in the second column)
If Condition 1 appears as DPP, Condition 2 cannot appear as lower high school or high school.
So there is only a dependency of random5 and random7 (resp. random6 and random8).
And this was, what I showed
Now you require a dependecy between random5 and random6
Does it mean: If in the first column there is DPP then in the second column there is only NPP and TPP?
Joffm
sorry, I do not understand why you suddenly wish a dependency between random5 and random6
this was your original code
Code:
<tr> <td bgcolor="#f2f2f2" style="text-align: center;"><span style="font-size:20px;"><strong><span style="color:#000000;"><span style="font-family:標楷體;">黨籍</span></span></strong></span></td> <td style="text-align: center;" width="1%"> </td> <td bgcolor="#f2f2f2" style="text-align: center;"><span style="font-size:20px;"><strong><span style="color:#000000;"><span style="font-family:標楷體;">{if(random5== 1, 'KMT',if(random5== 2, 'DPP',if(random5== 3, 'NPP',if(random5== 4, 'TPP','NA'))))}</span></span></strong></span></td> <td style="text-align: center;" width="1%"> </td> <td bgcolor="#f2f2f2" style="text-align: center;"><span style="font-size:20px;"><strong><span style="color:#000000;"><span style="font-family:標楷體;">{if(random6== 1, 'KMT',if(random6== 2, 'DPP',if(random6== 3, 'NPP',if(random6== 4, 'TPP','NA'))))}</span></span></strong></span></td> </tr> <tr style="height: 6px; text-align: center;"> </tr> <tr> <td bgcolor="#f2f2f2" style="text-align: center;"> <p><span style="font-size:20px;"><strong><span style="color:#000000;"> <font face="標楷體">學歷</font></span></strong></span></p> <p><span style="font-size:20px;"><strong><span style="color:#000000;"><font face="標楷體">前一份工作</font></span></strong></span></p> </td> <td style="text-align: center;" width="1%"> </td> <td bgcolor="#f2f2f2" style="text-align: center;"> <p><span style="font-size:20px;"><strong><span style="color:#000000;"><span style="font-family:標楷體;">{if(random7== 1, 'lower high school',if(random7== 2, 'high school',if(random7== 3, 'Under Graduate','Graduate')))}</span></span></strong></span></p> </td> <td style="text-align: center;" width="1%"> </td> <td bgcolor="#f2f2f2" style="text-align: center;"><span style="font-size:20px;"><strong><span style="color:#000000;"><span style="font-family:標楷體;">{if(random8== 1, 'lower high school',if(random8== 2, 'high school',if(random8== 3, 'Under Graduate','Graduate')))}</span></span></strong></span></td> </tr>
And this was your requirement
condition1: KMT/DPP/NPP/TPP/NP (this is random5 - in the first column, resp. random6 in the second column)
condition2: lower high school/high school/Undergraduate/Graduate (this is random7 - in the first column, resp. random8 in the second column)
If Condition 1 appears as DPP, Condition 2 cannot appear as lower high school or high school.
So there is only a dependency of random5 and random7 (resp. random6 and random8).
And this was, what I showed
{if(is_empty(random7),if(random5==2,rand(3, 4), rand(1,4)),random7)}
It is only:
If "random5" is equal 2 (DPP) then "random7" is a random number from 3-4, so 1(Lower high school) and 2(high school) will not be selected.
If "random5" is not equal 2 then "random7" is a random number from 1-4, so all degrees are possible.
Of course everything surrounded by the usual construct "if(!is_empty(randonnumber), "
I think this was your requirement.
Now you require a dependecy between random5 and random6
Does it mean: If in the first column there is DPP then in the second column there is only NPP and TPP?
Joffm
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11 months 3 weeks ago - 11 months 3 weeks ago #243129
by Joffm
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Replied by Joffm on topic Conjoint Analysis with some conditions
Hi,
why did you change your assignments:
In the original code
random5 and random6 were the "DPP/NPP/TPP" stuff
random7 and random8 were the degrees
Now you say:
random6 "1 = lower high school/ 2 = high school/ 3 = Undergraduate/ 4 = Graduate"
Do you want to confuse yourself or confuse us?
BTW:
You entered the equation into the question code of your table.
Of course you have to enter it as the alternative creation of the random number.
Joffm
why did you change your assignments:
In the original code
random5 and random6 were the "DPP/NPP/TPP" stuff
random7 and random8 were the degrees
Now you say:
random6 "1 = lower high school/ 2 = high school/ 3 = Undergraduate/ 4 = Graduate"
Do you want to confuse yourself or confuse us?
BTW:
You entered the equation into the question code of your table.
Of course you have to enter it as the alternative creation of the random number.
Joffm
Volunteers are not paid.
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Last edit: 11 months 3 weeks ago by Joffm.
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- RitaShen
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11 months 3 weeks ago - 11 months 3 weeks ago #243132
by RitaShen
Replied by RitaShen on topic Conjoint Analysis with some conditions
Dear Joffm,
I would like to express my sincere appreciation for your assistance, and my deepest apologies for any inconvenience caused. Initially, I had intended to simplify the table before seeking your guidance, but it appears that my actions have caused you some trouble. I deeply regret any inconvenience this may have caused you, and I am truly sorry.
And I've followed your code:
However, when I tested it, the number 2 still appeared.
Rita
I would like to express my sincere appreciation for your assistance, and my deepest apologies for any inconvenience caused. Initially, I had intended to simplify the table before seeking your guidance, but it appears that my actions have caused you some trouble. I deeply regret any inconvenience this may have caused you, and I am truly sorry.
And I've followed your code:
{if(is_empty(random6),if(random5==2,round(1.3*rand(1,3)), rand(1,4)),random6)}
rand(1,3) selects a random number 1, 2 or 3
so the result of 1.3*rand(1,3) is 1.3, 2.6 or 3.9
And after rounding you have your desired 1,3 and 4
However, when I tested it, the number 2 still appeared.
Rita
Last edit: 11 months 3 weeks ago by RitaShen.
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11 months 3 weeks ago - 11 months 3 weeks ago #243138
by Joffm
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Replied by Joffm on topic Conjoint Analysis with some conditions
What is the content of the cell.
I assume you entered the formula to create the random number.
No, you just replace your old
with
And in the table cell it is still
{if(random7== 1, 'KMT',if(random=7= 2, 'DPP',if(random7== 3, 'NPP',if(random7== 4, 'TPP','NA'))))}
or whatever
Joffm
I assume you entered the formula to create the random number.
No, you just replace your old
with
And in the table cell it is still
{if(random7== 1, 'KMT',if(random=7= 2, 'DPP',if(random7== 3, 'NPP',if(random7== 4, 'TPP','NA'))))}
or whatever
Joffm
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Last edit: 11 months 3 weeks ago by Joffm.
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- RitaShen
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11 months 3 weeks ago #243139
by RitaShen
Replied by RitaShen on topic Conjoint Analysis with some conditions
Joffm
here is the syntax in my cell
Rita
here is the syntax in my cell
Rita
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