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Hello everyone!

I have a survey with many multiple questions, and It will be distributed via Internet with one of those providers that pay for who is willing to answer it. One of the problems with this kind of approach is that some people just press the same option over and over, just to get their prize. Therefore, I want to avoid this.

My first approach was to use the "Question validation" feature, however, it just pops up a warning, and the person still can just change one answer and keep on. 

So I was willing to create a hidden question with the equation type that returns me 1 if all previous questions on the array have received the same answer, and 0 otherwise. WIth this, I can add a quota that doesn't allow it, and the respondent will be excluded from the survey.

Unfortunately, I haven't been able to program it by myself. I know that it might be something silly, but can anyone help me please?

Thanks in advance for your assistance. I'm attaching a sample survey with 1 similar question.

Hi,
read the manual about implemented functions
[url] manual.limesurvey.org/ExpressionScript_-...mplemented_functions [/url]
where you find the functions "count()" and  "countif()"

Now your equation will count each of your 5 answer options, like
countif("1",that.G01Q02.NAOK)
countif("2",that.G01Q02.NAOK)
...

If one of these counts is equal to  5, or more general (that it matches each number of subquestions) to "count(that.G01Q02)" you set the result to 1, else to 0.
And set your quota on this equation.

So:
{if(countif("1",that.G01Q02.NAOK)==count(that.G01Q02.NAOK) or countif("2",that.G01Q02.NAOK)==count(that.G01Q02.NAOK) or countif("3",that.G01Q02.NAOK)==count(that.G01Q02.NAOK) or countif("4",that.G01Q02.NAOK)==count(that.G01Q02.NAOK) or countif("5",that.G01Q02.NAOK)==count(that.G01Q02.NAOK),1,0)} 

Of course, you should use numerical codes- as I did. In your analysis you usually want to calculate some statistical measures, like mean, std.deviation, etc and also run some tests, like t-Test or ANOVA.
And really: the mean of "AO01" and "AO04" is not "AO02.5".   

Joffm

It worked flawlessly Joffm! Huge thanks!