Hi, there, I have a question about the question design issue, I don't know how it can work on LimeSurvey.

the Question is:

Q1a. How many statements are true in your case?
□None
□One item
□Two items
□Three items
□Four items


Q1b. How many statements are not true in your case?
□None
□One item
□Two items
□Three items
□Four items



If the respondents in Q1a answer None(0) and Q1b answer Two items(2), 0+2 is not equal to 4.
so it seems that the respondents miscounted, those people who miscounted will answer to the Q2.
if the respondetnts in Q1a answer One item(1) and Q1b answer Three items(3), 1+3 is equal to 4, so those people who answer the correct answer will go to answer the Q3.



simply put
Q1a+Q1b=4, answer the Q3.
Q1a+Q1b is not equal to 4, answer the Q2


is there anyone can help me to solve this issue?
many thanks


version:2.70.0+170921

Rita

Hi,
just set
relevance of Q2: sum(Q1a,Q1b)!=4
relevance of Q3: sum(Q1a,Q1b)==4




Joffm

thanks Joffm.

And now I have another question about this.

If the respondents in Q1a answer None(0) and Q1b answer Two items(2), 0+2 is not equal to 4. sum(Q1a,Q1b)!=4
the respondents are forbidden to answer the next page,
they must stay on this page until they choose the correct answer

could I do this in the limesurvey?

Hi, Rita,

assuming Q1 and Q2 are multiple questions and Q1_0 = None, you could set this as question validation in Q2:

((Q1_0=="Y") and (count(self)==4)) OR ((Q1_0!="Y") AND (sum(count(that.Q1),count(self))==4))

Best regards
Joffm

Sorry, Rita,

I did not realize that it's the same scenario (two single questions)

So, validate the second question by:

sum(that.Q1,self)==4

Regards
Joffm

Again sorry,

It was just a very - too - quick response.

Of course you have no validation in single punch questions.

Joffm