Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?

Mehr
3 Jahre 4 Monate her - 3 Jahre 4 Monate her #106340 von helviobrito
helviobrito erstellte das Thema Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?
:huh: Hi fellows.

Well, I`m here again. Hope someone can help me with this issue. And sorry my bad English. I am in Brazil.

I use LimeSurvey 2.05+ Build 140302.

I have a list radio question with 3 answers: 1 - aaaa, 2 - bbbb and 3 - NoAnswer. Just options 1 and 2 must be randomized. Option 3 should be fixed at the end. But I don't want NoAnswer in all my questions, so I set to "No" the specific option in General Settings.

Searching LimeSurvey Manual, I found two Workarounds with suggested scripts to do exactly what I need. I followed all the instructions, modifying the variables filterxsshtml to FALSE and shownoanswer to 0 in config.php, as stated, set the correct IDs in JavaScript, saved it in the source of the question, but nothing worked. All the answers were randomized.

What should I do? Can anyone help me? Keep in mind, fellows, that I'm not an IT professional. I'm a research specialist, very curious and darting in the mazes of coding.

Here are the Workarounds:

Partially Randomized Answers - Multiple Options & List (radio) questions - ENHANCED </br>
Partially Randomized Answers - Multiple Options & List (radio) questions

The scripts, with my sID, gID and qID. None worked, tested with Chrome, IE 9 and Firefox 20:

Dateianhang:

Dateiname: PartiallyR...ions.txt
Dateigröße:1 KB


Dateianhang:

Dateiname: PartiallyR...NCED.txt
Dateigröße:2 KB


Thanks.

Helvio Brito.
Anhang:
Letzte Änderung: 3 Jahre 4 Monate her von helviobrito.

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Mehr
3 Jahre 4 Monate her #106355 von tpartner
tpartner antwortete auf das Thema: Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?
I think we can clean up that workaround a bit.

Assuming your answers codes are sequential numbers and you have set the answers to be randomized, adding this script to the question source will always place the last answer item at the end of the list. (you do not need to worry about the question ID - it will be automatically detected)

<script type="text/javascript" charset="utf-8">	
 
	$(document).ready(function() {
 
		// Identify this question
		var qID = {QID}; 
 
		// Find the number of answers
		var ansCount = $('#question'+qID+' li.answer-item').length;
 
		// Place the last answer created at the end of the list
		var answer = $( 'input[id$="X'+qID+ansCount+'"]');
		var answerItem = $(answer).closest('li');
		var answersList = $(answer).closest('ul');
		$(answersList).append(answerItem);
 
	});
</script>

Here's a working survey:

Dateianhang:

Dateiname: limesurvey...7153.lss
Dateigröße:19 KB

Cheers,
Tony Partner
Solutions, code and workarounds presented in these forums are given without any warranty, implied or otherwise.
Anhang:
Folgende Benutzer bedankten sich: helviobrito

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Mehr
3 Jahre 4 Monate her #106369 von helviobrito
helviobrito antwortete auf das Thema: Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?
Thanks a lot, tpartner.

It works perfectly.

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Mehr
3 Jahre 4 Monate her - 3 Jahre 4 Monate her #106372 von helviobrito
helviobrito antwortete auf das Thema: Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?
Can I ask for more help?

If I want to set more than 1 answer to be fixed at the end of the list, what shoul I do?

e.g.:

1 - aaaa; 2 - bbbb; 3 - cccc; 4 - NoAnswer - 5 - OtherAnswer, randomizing itens 1, 2 and 3.

Thanks, again.
Letzte Änderung: 3 Jahre 4 Monate her von helviobrito.

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3 Jahre 4 Monate her - 3 Jahre 4 Monate her #106383 von tpartner
tpartner antwortete auf das Thema: Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?
Use this script and, if necessary, modify the "fixedAnswers" variable.

<script type="text/javascript" charset="utf-8">	
 
	$(document).ready(function() {
 
		// The number of answers to be fixed at the end of the list
		var fixedAnswers = 2;
 
		// Identify this question
		var qID = {QID}; 
 
		// Find the number of answers
		var ansCount = $('#question'+qID+' li.answer-item').length;
 
		// Place the last n answers created at the end of the list
		var fixedIndex = fixedAnswers - 1;
		for (var i=0; i<fixedAnswers; i++) {
			var answer = $( 'input[id$="X'+qID+(ansCount-fixedIndex)+'"]');
			var answerItem = $(answer).closest('li');
			var answersList = $(answer).closest('ul');
			$(answersList).append(answerItem);
			fixedIndex--;
		}		
	});
</script>

Here's a working survey:

Dateianhang:

Dateiname: Partially_...nced.lss
Dateigröße:20 KB

Cheers,
Tony Partner
Solutions, code and workarounds presented in these forums are given without any warranty, implied or otherwise.
Anhang:
Letzte Änderung: 3 Jahre 4 Monate her von tpartner.

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Mehr
3 Jahre 4 Monate her #106384 von tpartner
tpartner antwortete auf das Thema: Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?
I've updated the two workarounds:

Partially Randomized Answers - Multiple Options & List (radio) questions - manual.limesurvey.org/Workarounds:_Manip...28radio.29_questions

Partially Randomized Answers - Multiple Options & List (radio) questions (Enhanced) - manual.limesurvey.org/Workarounds:_Manip...tions_.28Enhanced.29


.

Cheers,
Tony Partner
Solutions, code and workarounds presented in these forums are given without any warranty, implied or otherwise.

Bitte Anmelden um der Konversation beizutretten.

Mehr
3 Jahre 4 Monate her #106385 von helviobrito
helviobrito antwortete auf das Thema: Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?
Thanks again and again. It's perfect.

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Mehr
2 Jahre 1 Monat her #121944 von LSdev
LSdev antwortete auf das Thema: Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?
Thanks tpartner for updating code. Many times we have to use the codes provided by client so we can not use sequential codes.I have one suggestion here. It will helpful if you can adapt your script so that it accepts an object specifying the response code and its position. I am thinking of using function like below :)
fixPostions({'respondseCode1':'position1','respondseCode2':'position2'})

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2 Jahre 1 Monat her - 2 Jahre 1 Monat her #122032 von tpartner
tpartner antwortete auf das Thema: Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?

It will helpful if you can adapt your script so that it accepts an object specifying the response code and its position...

That would require removing all of the specified answers from the list and then re-inserting them sequentially. Probably best done with a small jQuery pluging.

Add this plugin to the end of template.js:

	// A jQuery plugin to fix list-radio items in specific places
	// Requires a "positions" object with:
	// 		keys - numeric position, "first" or "last"
	//		values - answer codes
	(function( $ ){
 
		$.fn.lsRadioPositions = function(options) {  
 
			var opts = $.extend( {
				positions: {  }
			}, options);
 
			return this.each(function() { 
 
				var thisQuestion = $(this);
				var thisID = thisQuestion.attr('id').replace(/question/, '');
				var positionsArr = [];
 
				// Loop through the positions object
				$.each( opts.positions, function(position, code) {
					// Remove the option from the list
					$('li.answer-item[id$="X'+thisID+code+'"]').appendTo(thisQuestion);
 
					// Create an array of keys
					if (opts.positions.hasOwnProperty(position)) {
						if(position == 'first') {
							position = '1first';
						}
						positionsArr.push(position);
					}
				});
				positionsArr.sort();
 
				// Loop through the positions array
				$.each( positionsArr, function(i) {
 
					position = this;
					if(position == '1first') {
						position = 'first';
					}
					var thisCode = opts.positions[position]
 
					// Re-insert the option
					if(position == 'last') {
						$('ul.answers-list li.answer-item:last', thisQuestion).after($('li.answer-item[id$="X'+thisID+thisCode+'"]'));
					}
					else if(position == 1 || position == 'first') {
						$('ul.answers-list li.answer-item:first', thisQuestion).before($('li.answer-item[id$="X'+thisID+thisCode+'"]'));
					}
					else {
						$('ul.answers-list li.answer-item:eq('+(position-2)+')', thisQuestion).after($('li.answer-item[id$="X'+thisID+thisCode+'"]'));
					}
				});
			});
 
		};
	})( jQuery );


Then, call it something like this in the question source.
- Acceptable keys for the "positions" object are numeric position, "first" or "last".
- Values for the "positions" object are answer codes.
So, this example will always place answer codes A1 and A2 first and A6 last.

<script type="text/javascript" charset="utf-8">	
 
	$(document).ready(function() {		
 
		// Apply the radioPositions plugin to this question
		$('#question{QID}').lsRadioPositions( {
			positions: {
				2: 'A2', 
				last: 'A6', 
				first: 'A1'
			}
		} );  
    });
</script>


Sample survey:

Dateianhang:

Dateiname: limesurvey...4282.lss
Dateigröße:17 KB

Cheers,
Tony Partner
Solutions, code and workarounds presented in these forums are given without any warranty, implied or otherwise.
Anhang:
Letzte Änderung: 2 Jahre 1 Monat her von tpartner.
Folgende Benutzer bedankten sich: LSdev

Bitte Anmelden um der Konversation beizutretten.

Mehr
2 Jahre 1 Monat her #122046 von LSdev
LSdev antwortete auf das Thema: Help me: Partial randomized answers in LimeSurvey 2.05+ - How can I do this?
Superb as always !!!..:)

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